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600=1.5x^2
We move all terms to the left:
600-(1.5x^2)=0
We get rid of parentheses
-1.5x^2+600=0
a = -1.5; b = 0; c = +600;
Δ = b2-4ac
Δ = 02-4·(-1.5)·600
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*-1.5}=\frac{-60}{-3} =+20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*-1.5}=\frac{60}{-3} =-20 $
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